array_intersect_assoc
I have found the following helpful:
<?PHP
function array_merge_default($default, $data) {
$intersect = array_intersect_key($data, $default); //Get data for which a default exists
$diff = array_diff_key($default, $data); //Get defaults which are not present in data
return $diff + $intersect; //Arrays have different keys, return the union of the two
}
?>
It's use is like both of the functions it uses, but keeps defaults and _only_ defaults. It's designed for key arrays, and i'm not sure how it will work on numeric indexed arrays.
Example:
<?PHP
$default = array(
"one" => 1,
"two" => 2
);
$untrusted = array(
"one" => 42,
"three" => 3
);
var_dump(array_merge_default($default, $untrusted));
array(2) {
["two"]=>
int(2)
["one"]=>
int(42)
}
?>
array_intersect_key
(PHP 5 >= 5.1.0)
array_intersect_key — Computes the intersection of arrays using keys for comparison
Description
array array_intersect_key
( array $array1
, array $array2
[, array $ ...
] )
array_intersect_key() returns an array containing all the values of array1 which have matching keys that are present in all the arguments.
Parameters
- array1
-
The array with master keys to check.
- array2
-
An array to compare keys against.
- array
-
A variable list of arrays to compare.
Return Values
Returns an associative array containing all the values of array1 which have matching keys that are present in all arguments.
Examples
Example #1 array_intersect_key() example
<?php
$array1 = array('blue' => 1, 'red' => 2, 'green' => 3, 'purple' => 4);
$array2 = array('green' => 5, 'blue' => 6, 'yellow' => 7, 'cyan' => 8);
var_dump(array_intersect_key($array1, $array2));
?>
The above example will output:
array(2) { ["blue"]=> int(1) ["green"]=> int(3) }
In our example you see that only the keys 'blue' and 'green' are present in both arrays and thus returned. Also notice that the values for the keys 'blue' and 'green' differ between the two arrays. A match still occurs because only the keys are checked. The values returned are those of array1 .
The two keys from the key => value pairs are considered equal only if (string) $key1 === (string) $key2 . In other words a strict type check is executed so the string representation must be the same.
add a note
User Contributed Notesarray_intersect_key
CBWhiz at gmail dot com
05-Jan-2008 09:04
05-Jan-2008 09:04
Rod Byrnes
06-May-2007 02:10
06-May-2007 02:10
Here is a faster version than those shown below, with optimisation for the case when only two arrays are passed. In my tests with a 10000 item first array and a 5000 item second array (run 20 times) this function ran in 1.89 seconds compared with 2.66 for the version posted by dak. For a three array case, same as above but with the third array containing 3333 values, the timing is 3.25 for this version compared with 3.7 for dak's version.
<?php
if (!function_exists('array_intersect_key'))
{
function array_intersect_key($isec, $keys)
{
$argc = func_num_args();
if ($argc > 2)
{
for ($i = 1; !empty($isec) && $i < $argc; $i++)
{
$arr = func_get_arg($i);
foreach (array_keys($isec) as $key)
{
if (!isset($arr[$key]))
{
unset($isec[$key]);
}
}
}
return $isec;
}
else
{
$res = array();
foreach (array_keys($isec) as $key)
{
if (isset($keys[$key]))
{
$res[$key] = $isec[$key];
}
}
return $res;
}
}
}
?>
17-Jul-2006 10:31
Here it is a more obvious way to implement the function:
if (!function_exists('array_intersect_key')) {
function array_intersect_key()
{
$arrs = func_get_args();
$result = array_shift($arrs);
foreach ($arrs as $array) {
foreach ($result as $key => $v) {
if (!array_key_exists($key, $array)) {
unset($result[$key]);
}
}
}
return $result;
}
}
Anton Backer
31-Mar-2006 06:49
31-Mar-2006 06:49
Jesse: no, array_intersect_key does not accomplish the same thing as what you posted:
array_flip (array_intersect (array_flip ($a), array_flip ($b)))
because when the array is flipped, values become keys. having duplicate values is not a problem, but having duplicate keys is. array_flip resolves it by keeping only one of the duplicates and discarding the rest. by the time you start intersecting, you've already lost information.
dak
24-Jan-2006 03:31
24-Jan-2006 03:31
A more efficient (and, I think, simpler) compatibility implementation:
<?php
if (!function_exists('array_intersect_key'))
{
function array_intersect_key ($isec, $arr2)
{
$argc = func_num_args();
for ($i = 1; !empty($isec) && $i < $argc; $i++)
{
$arr = func_get_arg($i);
foreach ($isec as $k =>& $v)
if (!isset($arr[$k]))
unset($isec[$k]);
}
return $isec;
}
}
?>
Silvio Ginter
23-Sep-2005 10:17
23-Sep-2005 10:17
Based on the code posted by gaylord dot aulke at 100days.de
i wrote this one. This should implement this function in all versions equal or greater than PHP 4.0
function array_intersect_key($arr1, $arr2) {
$res = array();
foreach($arr1 as $key=>$value) {
$push = true;
for ($i = 1; $i < func_num_args(); $i++) {
$actArray = func_get_arg($i);
if (gettype($actArray) != 'array') return false;
if (!array_key_exists($key, $actArray)) $push = false;
}
if ($push) $res[$key] = $arr1[$key];
}
return $res;
}
gaylord dot aulke at 100days.de
04-Jul-2005 09:04
04-Jul-2005 09:04
I tried to use this function with PHP 5.0.4 under windows but the function does not seem to be implemented.
(Fatal error: Call to undefined function array_intersect_key())
This works as a workaround for 2 arrays at least:
function array_intersect_key($arr1, $arr2) {
$res = array();
foreach($arr1 as $key=>$value) {
if(array_key_exists($key, $arr2)) $res[$key] = $arr1[$key];
}
return $res;
}
aidan at php dot net
30-May-2005 01:51
30-May-2005 01:51
This functionality is now implemented in the PEAR package PHP_Compat.
More information about using this function without upgrading your version of PHP can be found on the below link:
http://pear.php.net/package/PHP_Compat